Asked by kike paul

I tried all the formulas i know but i cannot answer it I really need your help in this question..
A projectile was launched 64° above the horizontal, attaining a height of 10 m. What is the projectile's initial speed?

Answers

Answered by drwls
You can apply conservation of energy to the vertical velocity component, since the horizontal component does not change.

(Vo sin64)^2/2 = g H = 98 m^2/s^2
Vo sin64 = 196
Vo sin64 = 14
Vo = 15.6 m/s
Answered by kike paul
thanks
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