Asked by Madison
Ive tried using the formulas my teacher gave me, however I can't seem to get the right answers. Please help!
A 1.4-kg block hangs from a spring. A 363-g body hung below the block stretches the spring 2.6 cm farther. What is the spring constant?
When the 363-g body is removed the block is set into oscillation. Find the period of this motion.
A 1.4-kg block hangs from a spring. A 363-g body hung below the block stretches the spring 2.6 cm farther. What is the spring constant?
When the 363-g body is removed the block is set into oscillation. Find the period of this motion.
Answers
Answered by
Elena
m₂g=kx
k= m₂g/x=0.363•9.8/0.026 = 136.8 N/mþ
T=2π•sqrt(m₁/k) =
=2π•sqrt(1.4/136.8)=0.64 s
k= m₂g/x=0.363•9.8/0.026 = 136.8 N/mþ
T=2π•sqrt(m₁/k) =
=2π•sqrt(1.4/136.8)=0.64 s
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