Asked by Amy
                Alaskan moose can be as massive as 800 kg. Suppose two feuding moose, both of which have a mass of 800 kg, back away and then run toward each other. If one of them runs to the left with a speed of 6.0 m/s, and the other runs to the right with a speed of 8.0 m/s, what amount of kinetic energy will be dissipated after their inelastic collision?
            
            
        Answers
                    Answered by
            drwls
            
    You are probably supposed to assume that they stick together, with total momentum conserved. In that case, they end up traveling both at a speed V such that
1600*V = 800*8.0 - 800*6.0
V = 1.0 m/s
K.E. dissipated
= Initial KE - final KE
= (1/2)(2)*800*(8^2+6^2 - (1/2)1600*1^2
= 800*[100 - 1) = 79,200 J
    
1600*V = 800*8.0 - 800*6.0
V = 1.0 m/s
K.E. dissipated
= Initial KE - final KE
= (1/2)(2)*800*(8^2+6^2 - (1/2)1600*1^2
= 800*[100 - 1) = 79,200 J
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.