You are probably supposed to assume that they stick together, with total momentum conserved. In that case, they end up traveling both at a speed V such that
1600*V = 800*8.0 - 800*6.0
V = 1.0 m/s
K.E. dissipated
= Initial KE - final KE
= (1/2)(2)*800*(8^2+6^2 - (1/2)1600*1^2
= 800*[100 - 1) = 79,200 J
Alaskan moose can be as massive as 800 kg. Suppose two feuding moose, both of which have a mass of 800 kg, back away and then run toward each other. If one of them runs to the left with a speed of 6.0 m/s, and the other runs to the right with a speed of 8.0 m/s, what amount of kinetic energy will be dissipated after their inelastic collision?
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