Asked by Aman
Find the angles between the following pairs of vectors
(1)3i+2j-6k,4i-3j+k
(2)2i-3j+k,3i-j-2k
(1)3i+2j-6k,4i-3j+k
(2)2i-3j+k,3i-j-2k
Answers
Answered by
Reiny
1.
your 2 vectors are [3,2,-6] and [4,-3,1]
using the dot product
12 - 6 - 6 = √(9+4+36) √(16+9+1) cosØ, where Ø is the angle between them
0 = .... , no point to go further.
I can see cosØ = 0
Ø = 90° or π/2 radians
2.
6 + 3 - 2 = √(4+9+1) √(9+1+4) cosØ
7 = √14√14cosØ
7 = 14cosØ
cosØ = 1/2
Ø = 60° or π/3
your 2 vectors are [3,2,-6] and [4,-3,1]
using the dot product
12 - 6 - 6 = √(9+4+36) √(16+9+1) cosØ, where Ø is the angle between them
0 = .... , no point to go further.
I can see cosØ = 0
Ø = 90° or π/2 radians
2.
6 + 3 - 2 = √(4+9+1) √(9+1+4) cosØ
7 = √14√14cosØ
7 = 14cosØ
cosØ = 1/2
Ø = 60° or π/3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.