Asked by Jin Hwang

The cable supporting a 2123 kg elevator has a maximum strength of 25982 N. What maximum upward acceleration can it give the elevator without breaking?

Can someone give me step by step on how to solve this?
Answered by Damon
F = m a
25982 - m g = ma

25982 = 2123 (a + 9.81)
Answered by Elias
A car starts from rest and travels for 6.0 s with a uniform acceleration of +1.5 m/s2. The driver then applies the brakes, causing a uniform acceleration of -2.0 m/s2. If the brakes are applied for 3.0 s, how fast is the car going at the end of the braking period?

damon can u help me?
Answered by Jin Hwang
Hey Damon, i'm not sure if i calculated wrong, but was I supposed to do
(2123)(9.81a) = 20826.63a
then divide 25982a/20826.63?
Answered by Jin Hwang
Oh, nvm haha I'm an idiot. I got it THANKS A BUNCH!
Answered by Elias
care to help me out jin hwang?
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