Question
If A = [12-23], B=[2123] and C=[-3120] verify that A(B+c) = AB+AC
Answers
Answered by
oobleck
given the context, I suspect that A,B,C are all 2x2 matrices.
Try that on for size.
Try that on for size.
Answered by
GPT 3.5
To solve this equation, we need to perform the operations on both sides and see if they are equal:
A = [12-23]
B = [2 1 2 3]
C = [-3 1 2 0]
A(B + C) = [12 - 23]([2 1 2 3] + [-3 1 2 0])
First, we need to perform the operation inside the parentheses:
[2 1 2 3] + [-3 1 2 0] = [-1 2 4 3]
Now, we can multiply A by the sum:
[12 - 23]([-1 2 4 3]) = [-12 24 48 36 -23 -46 -92 -69]
Next, we need to calculate AB and AC:
AB = [12-23][2 1 2 3] = [24 12 24 36 -46 -23 -46 -69]
AC = [12-23][-3 1 2 0] = [-36 12 24 0 69 -23 -46 0]
Finally, we add AB and AC:
[24 12 24 36 -46 -23 -46 -69] + [-36 12 24 0 69 -23 -46 0] = [-12 24 48 36 -23 -46 -92 -69]
Therefore, A(B + C) = AB + AC, and the equation is verified.
A = [12-23]
B = [2 1 2 3]
C = [-3 1 2 0]
A(B + C) = [12 - 23]([2 1 2 3] + [-3 1 2 0])
First, we need to perform the operation inside the parentheses:
[2 1 2 3] + [-3 1 2 0] = [-1 2 4 3]
Now, we can multiply A by the sum:
[12 - 23]([-1 2 4 3]) = [-12 24 48 36 -23 -46 -92 -69]
Next, we need to calculate AB and AC:
AB = [12-23][2 1 2 3] = [24 12 24 36 -46 -23 -46 -69]
AC = [12-23][-3 1 2 0] = [-36 12 24 0 69 -23 -46 0]
Finally, we add AB and AC:
[24 12 24 36 -46 -23 -46 -69] + [-36 12 24 0 69 -23 -46 0] = [-12 24 48 36 -23 -46 -92 -69]
Therefore, A(B + C) = AB + AC, and the equation is verified.
Answered by
GPT 3.5
Apologies for the confusion. Let's assume A, B, and C are all 2x2 matrices and verify the equation.
A = [12 -23]
B = [2 1]
[2 3]
C = [-3 1]
[2 0]
Now, let's calculate A(B + C):
B + C = [2 1] + [-3 1] = [-1 2]
[4 3]
Multiplying A by (B + C):
A(B + C) = [12 -23]([-1 2]) = [24 - 49]
[-24 -21]
Next, let's calculate AB and AC:
AB = [12 -23][2 1] = [24 - 49]
[20 - 43]
AC = [12 -23][-3 1] = [9 - 35]
[-6 2]
Finally, let's add AB and AC:
AB + AC = [24 - 49] + [9 - 35] = [33 - 84]
[14 - 41]
Hence, A(B + C) is not equal to AB + AC in this case.
A = [12 -23]
B = [2 1]
[2 3]
C = [-3 1]
[2 0]
Now, let's calculate A(B + C):
B + C = [2 1] + [-3 1] = [-1 2]
[4 3]
Multiplying A by (B + C):
A(B + C) = [12 -23]([-1 2]) = [24 - 49]
[-24 -21]
Next, let's calculate AB and AC:
AB = [12 -23][2 1] = [24 - 49]
[20 - 43]
AC = [12 -23][-3 1] = [9 - 35]
[-6 2]
Finally, let's add AB and AC:
AB + AC = [24 - 49] + [9 - 35] = [33 - 84]
[14 - 41]
Hence, A(B + C) is not equal to AB + AC in this case.