F = ma
1.5 = .2 a
7.5 = a
s = 1/2 at^2
.3 = 3.75 t^2
t = .2828
v = at
= 7.5*.2828
= 2.12
Of course, by combining all those formulas, you could have just used
v = sqrt(2sF/m)
A 1.5 N force acts on a .20 kg cart so as to accelerate it along a frictionless track. If it is accelerated from rest, how fast is it going after .3m?
The answer given is 2.12 m/s but I am not sure how to get to that.
1 answer
1 answer