Asked by jay
The width of a rectangle is 6 cm less than its length. If the area of the rectangle is 135 square cm, find the dimensions. Then find the perimeter of the rectangle.
Answers
Answered by
Bosnian
W = Width
L = Length
A = Area
W = L - 6
A = W * L
135 =( L - 6 ) * L
135 = L ^ 2 - 6 L
The exact solution are :
L = - 9 cm
and
L = 15 cm
The length can't be negative so:
L = 15 cm
W = L - 6
W = 15 - 6 = 9 cm
A = W * L = 15 * 9 = 135 cm ^ 2
P. S.
If you don't know how to solve equation:
135 = L ^ 2 - 6 L
Go on:
wolframalpha dot com
When page be open in rectangle type:
solve 135 = L ^ 2 - 6 L
and click option =
After few seconds when you see result click option:
Show steps
L = Length
A = Area
W = L - 6
A = W * L
135 =( L - 6 ) * L
135 = L ^ 2 - 6 L
The exact solution are :
L = - 9 cm
and
L = 15 cm
The length can't be negative so:
L = 15 cm
W = L - 6
W = 15 - 6 = 9 cm
A = W * L = 15 * 9 = 135 cm ^ 2
P. S.
If you don't know how to solve equation:
135 = L ^ 2 - 6 L
Go on:
wolframalpha dot com
When page be open in rectangle type:
solve 135 = L ^ 2 - 6 L
and click option =
After few seconds when you see result click option:
Show steps
Answered by
Anonymous
perimeter of a rectangle with length 6.6m and width 4.5
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