Asked by Anonymous
the longer base of an isosceles trapezoid is 14 feet. the nonparallel sides are each 10 feet long and the length of diagonal is 16 feet. find the measure of a base angle
Answers
Answered by
MathMate
So we have a trapezoid ABCD, in which
AB=unknown
BC=10,
CD=14
DA=10
and
AC=16.
Sketch the triangle ACD for which the lengths of all three sides are known.
Using the cosine rule, calculate the cosine of A using
cosA=(AC²+AD²-CD²)/(2*AC*AD)
and hence calculate ∠A.
AB=unknown
BC=10,
CD=14
DA=10
and
AC=16.
Sketch the triangle ACD for which the lengths of all three sides are known.
Using the cosine rule, calculate the cosine of A using
cosA=(AC²+AD²-CD²)/(2*AC*AD)
and hence calculate ∠A.
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