Question

I have seven homework problems. I did them but I wasn't sure if I did them correctly. Did I do them correct? Thank you!


Give the reaction that describes how the hydrazine, N2H4(aq), / hydrazinium ion, N2H51+(aq), buffer reacts with a strong base such as sodium hydroxide.

N2H4(aq) + OH^1-(aq) --> N2H51+(aq) + H2O(l)

Give the reaction that describes how the sodium bicarbonate / sodium carbonate buffer reacts with a strong base such as sodium hydroxide

H2CO3(aq) + OH^1-(aq) --> HCO3^1-(aq) + H2O(l)

Give the reaction that describes how the sodium hydrogen phosphate / sodium phosphate buffer reacts with a strong base such as sodium hydroxide

HPO4^2-(aq) + OH^1-(aq) --> PO4^3-(aq) + H2O(l)

Give the reaction that describes how the trimethylamine, (CH3)3N(aq) / trimethylammonium ion, (CH3)3NH1+(aq), buffer reacts with a strong acid such as hydrochloric acid

(CH3)3NH1+(aq) + H3O^1+(aq) --> (CH3)3N(aq) + H2O(l)

Give the reaction that describes how the ethylamine, C2H5NH2(aq), / ethylammonium ion, C2H5NH31+(aq), buffer reacts with a strong acid such as hydrochloric acid

C2H5NH31+(aq) + H3O^1+(aq) --> C2H5NH2(aq) + H2O(l)

Give the reaction that describes how the hydrofluoric acid / sodium fluoride buffer reacts with a strong acid such as hydrochloric acid.

F^1-(aq) + H3O^1+(aq) --> HF(aq) + H2O(l)

Answer 1

Give the reaction that describes how the hydrazine, N2H4(aq), / hydrazinium ion, N2H51+(aq), buffer reacts with a strong base such as sodium hydroxide.

N2H4(aq) + OH^1-(aq) --> N2H51+(aq) + H2O(l)

<b>I don't think so. The OH^- will react with the acid, N2H5^+, like this
N2H5^+ + OH^- ==> H2O + N2H4</b>

Give the reaction that describes how the sodium bicarbonate / sodium carbonate buffer reacts with a strong base such as sodium hydroxide

H2CO3(aq) + OH^1-(aq) --> HCO3^1-(aq) + H2O(l)
<b>HCO3^- is the acid in the HCO3^-/CO3^2- system. H2CO3 isn't there so you can't use that.
HCO3^- + OH^- ==> H2O + CO3^2-</b>

Give the reaction that describes how the sodium hydrogen phosphate / sodium phosphate buffer reacts with a strong base such as sodium hydroxide

HPO4^2-(aq) + OH^1-(aq) --> PO4^3-(aq) + H2O(l)
<b>This looks ok.</b>

Give the reaction that describes how the trimethylamine, (CH3)3N(aq) / trimethylammonium ion, (CH3)3NH1+(aq), buffer reacts with a strong acid such as hydrochloric acid

(CH3)3NH1+(aq) + H3O^1+(aq) --> (CH3)3N(aq) + H2O(l)
<b> The base is what reacts with the acid; therefore,
(CH3)3N(aq) + HCl ==> (CH3)3NH^+ + Cl^-</b>

Give the reaction that describes how the ethylamine, C2H5NH2(aq), / ethylammonium ion, C2H5NH31+(aq), buffer reacts with a strong acid such as hydrochloric acid

C2H5NH31+(aq) + H3O^1+(aq) --> C2H5NH2(aq) + H2O(l)
<b> Same comment as the trimethylamine above.</b>

Give the reaction that describes how the hydrofluoric acid / sodium fluoride buffer reacts with a strong acid such as hydrochloric acid.

F^1-(aq) + H3O^1+(aq) --> HF(aq) + H2O(l)
<b>This looks ok to me.</b>