Question

I need help on this homework problem and I do not understand how to work on it. Please help me with this problem.

The photoelectric work function of a metal is the minimum energy needed to eject an electron by irradiating the metal with light. For calcium, this work function equals 4.34X10^(-19)J. What is the minimum frequency of light required to observe the photoelectric effect in calcium?

Answer 1

This question should have been posted on the PHYSICS board.

Answer 2

delta E = hf
Substitute 4.34 x 10^-19 for delta E, substitute Planck's constant for h and calculate frequency.

Answer 3

1.53e-15