Asked by Mai

I need help on this homework problem and I do not understand how to work on it. Please help me with this problem.

The photoelectric work function of a metal is the minimum energy needed to eject an electron by irradiating the metal with light. For calcium, this work function equals 4.34X10^(-19)J. What is the minimum frequency of light required to observe the photoelectric effect in calcium?
Answered by GK
This question should have been posted on the PHYSICS board.
Answered by DrBob222
delta E = hf
Substitute 4.34 x 10^-19 for delta E, substitute Planck's constant for h and calculate frequency.
Answered by Anonymous
1.53e-15
There are no AI answers yet. The ability to request AI answers is coming soon!