​$6300 is​ invested, part of it at 11​% and part of it at 77​%. For a certain​ year, the total yield is ​$565.00. How much was invested at each​ rate?

how much was invested at 11% and 7%?

thank you

1 answer

If $x at 11%, then the rest $(6300-x) is at 7%. So, just add up the interest:

.11x + .07(6300-x) = 565