Asked by math

​$6300 is​ invested, part of it at 11​% and part of it at 77​%. For a certain​ year, the total yield is ​$565.00. How much was invested at each​ rate?

how much was invested at 11% and 7%?



thank you

Answers

Answered by Steve
If $x at 11%, then the rest $(6300-x) is at 7%. So, just add up the interest:

.11x + .07(6300-x) = 565
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