Asked by math
$6300 is invested, part of it at 11% and part of it at 77%. For a certain year, the total yield is $565.00. How much was invested at each rate?
how much was invested at 11% and 7%?
thank you
how much was invested at 11% and 7%?
thank you
Answers
Answered by
Steve
If $x at 11%, then the rest $(6300-x) is at 7%. So, just add up the interest:
.11x + .07(6300-x) = 565
.11x + .07(6300-x) = 565
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