Question

$6300 is​ invested, part of it at 11​% and part of it at 8​%. For a certain​ year, the total yield is ​$nbsp 597.00 . How much was invested at each​ rate?

x+y=6300(-11)
0.11x+ 0.08y=597(100)
............................
11x+8y=59700
-11x−11y=−69300
...........................
−3y=−9600
y=3200
........................
x+3200=6300
x=3100

Answer 1

correct

There are some minor flaws in your presentation

x+y=6300(-11) should have been
-11(x+y)=6300(-11) to get
-11x -11y = -69300

0.11x+ 0.08y=597(100) should have said
100(0.11x+ 0.08y)=597(100) to get
11x + 8y = 59700

The way you have it, the left side is not equal to the right side