Asked by Brooke
Suppose the ball is kicked horizontally with an initial speed of 9.37m/s. If the ball travels a horizontal distance of distnace 85 meters, how tall is the mountain?
Answers
Answered by
Henry
R = 9.39T = 85m.
T = 9.05s = Time in flight.
Tr - Tf = T/2 = 9.05 / 2 = 4.53s. = Rise time = Fall time.
h = V0*t + 0.5g*t^2,
h = 0 + 4.9(4.53)^2 = 101m.
T = 9.05s = Time in flight.
Tr - Tf = T/2 = 9.05 / 2 = 4.53s. = Rise time = Fall time.
h = V0*t + 0.5g*t^2,
h = 0 + 4.9(4.53)^2 = 101m.
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