Asked by Erin
a ball is kicked in the air from the top of a cliff , the path that the ball travels is given by the equation
h(t)=-5t^2+17t+22, where h(t) is the height given in meters and t is the time seconds.
a) how high is the cliff ?
b)what is the maximum height the ball reaches ?
c)when will the ball hit the ground
d)write an equation for the axis of symmetry
e)determine the domain and range of the function
h(t)=-5t^2+17t+22, where h(t) is the height given in meters and t is the time seconds.
a) how high is the cliff ?
b)what is the maximum height the ball reaches ?
c)when will the ball hit the ground
d)write an equation for the axis of symmetry
e)determine the domain and range of the function
Answers
Answered by
Reiny
a) would you not be on top of the cliff if t = 0
b) change the equation to vertex form
h(t) = a(t-h)^2 + k
the value of k will be your maximum height
c) set h(t) = 0 and solve for t as a quadratic
d) once you have the equation in b) the axis of symmetry will be t = h
e) your sketch of the graph will let you determine domain and range.
hint: the t value of the vertex (t,k) is 1.7
b) change the equation to vertex form
h(t) = a(t-h)^2 + k
the value of k will be your maximum height
c) set h(t) = 0 and solve for t as a quadratic
d) once you have the equation in b) the axis of symmetry will be t = h
e) your sketch of the graph will let you determine domain and range.
hint: the t value of the vertex (t,k) is 1.7
Answered by
Erin
Thankss !!
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