Question

find the derivative of:

g(x) = log[(x^3+1)^3(x^3-1)^3)]

Answer 1

Go on:

wolframalpha dot com

When page be open in rectangle type:

derivative log[(x^3+1)^3(x^3-1)^3)]

and click option =

After few seconds when you see result click option:

Show steps


On wolframalpha dot com you can practice any kind of calculus.

Answer 2

woah, now this will make my life so much easier, thank you

Answer 3

except that page teaches you nothing, what are you going to do on a test?

g(x) = ln[(x^3+1)^3(x^3-1)^3)]
= 3 ln(x^3 + 1) + 3 ln (x^3 - 1)
g'(x) = 3(3x^2)/(x^3+1) + 3(3x^2)/(x^3 - 1)
= 9x^2/(x^3+1) + 9x^2/(x^3-1)

The Wolfram page assumed that you meant ln

another way is to simplify the original

RS = ln [(x^3+1)(x^3-1) ]^3
= ln (x^6 -1)^3

g(x) = ln (x^6 - 1)^3
= 3 ln(x^6 - 1)
g'(x) =3(6x^5)/(x^6 - 1) = 18x^5/(x^6 - 1)

Answer 4

Solve the following inequality. Then place the correct answer in the box provided. Answer in terms of an improper fraction.

3y + 5 >10