Asked by Matt
Find the derivative if y=sec^-1 (x+3)
Please any help.
Please any help.
Answers
Answered by
drwls
Look up the derivative of arc-secant.
If y = sec^-1 u,
dy/du = 1/[u sqrt(u^2-1)]
Then let x+3 = u and use the chain rule. dy/dx = dy/du * du/dx
If y = sec^-1 u,
dy/du = 1/[u sqrt(u^2-1)]
Then let x+3 = u and use the chain rule. dy/dx = dy/du * du/dx
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