Asked by Shellby

Consider the combustion of propane:
C3H8(g)+5O2(g) yields 3CO2(g) + 4H2O(l)
delta H= -2221 kJ
Assume that all of the heat comes from the combustion of propane. Calculate delta H in which 5.00g of propane is burned in excess oxygen at constant pressure.
Answered by DrBob222
-2221 kJ x (5/molar mass C3H8) = ?
Answered by Anonymous
-252.4
Answered by Henry Perry
Find the number moles and of is equal to 0.1136mol
then multiply the delta H=-2221KJ
finally the answer is equal to -252.3KJ
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