Asked by Toya

Titration of 25.00 mL of KOH required 200.00 mL of 0.0050 M acetic acid, CH3COOH. What is the molarity (M) of the KOH solution? Please show calcutions.
Answered by DrBob222
HAc = CH3COOH = acetic acid
KOH = potassium hydroxide
mL KOH x M KOH = mL HAc x M HAc
Substitute and solve for M KOH
Answered by Anonymous
0.04
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