Asked by Ashley
a hot air balloon is rising vertically 10 ft/sec while the wind is blowing horizontally 5ft/sec. Find the speed of the balloon and the angle x that it makes with the horizontal.
I know that the speed of the balloon is
the square root of (10)^2 + (5)^2, but I was wondering if someone could tell me why the speed is equal to that. Thanks.
I know that the speed of the balloon is
the square root of (10)^2 + (5)^2, but I was wondering if someone could tell me why the speed is equal to that. Thanks.
Answers
Answered by
Steve
Every second the balloon rises 10 ft and moves sideways 5 feet.
So, the distance traveled in one second is sqrt(10^2 + 5^2)
Since it traveled that distance in one second, and speed is distance/time, the same triangle can be used to calculate the speed.
So, the distance traveled in one second is sqrt(10^2 + 5^2)
Since it traveled that distance in one second, and speed is distance/time, the same triangle can be used to calculate the speed.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.