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Original Question
Suppose one card is selected at random from an ordinary deck of 52 playing cards. Let A= event a diamond is selected B=event a...Asked by HM
Suppose one card is selected at random from an ordinary deck of 52 playing cards.
Let
A= event a diamond is selected
B=event a club is selected
Determine P(A|(not B))
Could some one explain this to me and tell me how they got the answer
Let
A= event a diamond is selected
B=event a club is selected
Determine P(A|(not B))
Could some one explain this to me and tell me how they got the answer
Answers
Answered by
bobpursley
if NOt B, then the card has to be a diamond, heart, or spade.
Pr(A|NOT B)=1/3
Pr(A|NOT B)=1/3
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