Asked by Anthony
A golf ball is drive. With an initial velocity of 25 m/s at an angle of 35 degrees with the horizontal find the maximum height the ball reaches above its original height
Answers
Answered by
bobpursley
max height is when vertical velocity is zero.
vf=vi+gt
0=25sin35 -9.8t solve for t.
then, hmax=25sin35*t-1/2 g t^2
vf=vi+gt
0=25sin35 -9.8t solve for t.
then, hmax=25sin35*t-1/2 g t^2
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