A golf ball is hit off the top of a cliff that is 75 feet tall at an angle of 45° to the horizontal with an initial velocity of 80 feet per second. The quadratic equation shown below models the height, h(x), of the ball when it is x feet from the cliff’s edge. How far will the ball travel until it hits the ground? Round your answer to the nearest hundredth of a second.
I got 233.25. Is this correct?
2 answers
Nevermind, I worked the answer out
h(t) = 75 + 80/√2 t - 16t^2
h=0 when t=4.563
The horizontal speed is a constant 80/√2 = 56.57 ft/s
So, the ball travels 258.12 ft
Hmm. We differ slightly. What did you do? And of course, check my math.
h=0 when t=4.563
The horizontal speed is a constant 80/√2 = 56.57 ft/s
So, the ball travels 258.12 ft
Hmm. We differ slightly. What did you do? And of course, check my math.