Asked by kate
At an outdoor market, a bunch of bananas attached to the bottom of a vertical spring of force constant 16.0 N/m is set into oscillatory motion with an amplitude of 20.0 cm. It is observed that the maximum speed of the bunch of bananas is 39.6 cm/s. What is the weight of the bananas in newtons?
Answers
Answered by
Writeacher
Your umpteen posts have been removed.
Once you write up <b>YOUR THOUGHTS</b>, please re-post, and someone here will be happy to comment.
Once you write up <b>YOUR THOUGHTS</b>, please re-post, and someone here will be happy to comment.
Answered by
drwls
Try using the fact that the maximum kinetic energy , (1/2)MVmax^2
is equal to the initial potential energy stored in the spring,
(1/2) k X^2.
Then solve for Vmax
k is the spring force constant, which you have been given. X is the starting (and maximum) deflection
is equal to the initial potential energy stored in the spring,
(1/2) k X^2.
Then solve for Vmax
k is the spring force constant, which you have been given. X is the starting (and maximum) deflection
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.