Asked by dream

A new Outdoor Recreation Center is being built in Erie. The perimeter of the rectangular playing field is 450 yards. The length of the field is 3 yards less than triple the width. What are the dimensions of the playing field? Show your work.
Answered by R_scott
2 (L + W) = 450 ... L + W = 225

L + 3 = W

substituting ... L + L + 3 = 225

solve for L , then subtitute back to find W
Answered by dream
thank you, but im still confused. could you help me out with the last bit? i cant figure out the width
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