Asked by Bill
solve (x+17)(x-6)(x+14)>0
Answers
Answered by
Reiny
consider
y = (x+17)(x-6)(x+14)
this cubic would have x-intercepts at
x = -17, -14, and 6
its first term is x^3, so it would rise in the 1st quadrant.
So the curve is above the x-axis, or positive for
-17 < x < -14 or x > 6
y = (x+17)(x-6)(x+14)
this cubic would have x-intercepts at
x = -17, -14, and 6
its first term is x^3, so it would rise in the 1st quadrant.
So the curve is above the x-axis, or positive for
-17 < x < -14 or x > 6
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.