Asked by Nashaly

In a car crash, a 44 kilogram passenger moving at 15 meters per second is brought to rest by an air bag during a 0.10 second time interval. What is the magnitude of the average force exerted on the passenger during this time?
Answered by drwls
(average force)*(time interval) = (momentum change) = 44*15 = 660 kg m/s

Solve for the average force, which will be in newtons
Answered by Jane
6600 N
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