Asked by Mishaka
Using the product rule, find the derivative of the following function:
(x^1/2 cscx sinx).
(x^1/2 cscx sinx).
Answers
Answered by
Steve
First off, csc * sin = 1
So, y = √x
However, if you insist on doing it the hard way
y = √x cscx sinx
y' = 1/2√x cscx sinx + √x(cscx sinx)'
= 1/2√x * 1 + √x(-cscx ctnx * sinx + cscx cosx)
= 1/2√x + √x(-ctnx + ctnx)
= 1/2√x
same answer
So, y = √x
However, if you insist on doing it the hard way
y = √x cscx sinx
y' = 1/2√x cscx sinx + √x(cscx sinx)'
= 1/2√x * 1 + √x(-cscx ctnx * sinx + cscx cosx)
= 1/2√x + √x(-ctnx + ctnx)
= 1/2√x
same answer
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