Asked by archi
If two resistors R1 and R2 are connected in parallel, then the total resistance R measured in ohms is given by
1/R=1/R1+1/R2
If the resistance of R1 and R2 are increasing at 330 and 660 ohms per second respectively, then the rate of increase of R when R1=5000 and R2=5000 is how many ohms per second?
1/R=1/R1+1/R2
If the resistance of R1 and R2 are increasing at 330 and 660 ohms per second respectively, then the rate of increase of R when R1=5000 and R2=5000 is how many ohms per second?
Answers
Answered by
Steve
Just plug and chug
1/R = 1/R1 + 1/R2
1/R = 1/5000 + 1/5000 = 2/5000
R = 2500
-1/R^2 R' = -1/R1^2 R1' - 1/R2^2 R2'
-1/625E4 R' = -1/25E6 * 330 - 1/25E6 * 660
1/625E4 R' = 990/25E6
R' = 990*625E4/25E6 = 990*625/2500
R' = 247.5 ω/s
1/R = 1/R1 + 1/R2
1/R = 1/5000 + 1/5000 = 2/5000
R = 2500
-1/R^2 R' = -1/R1^2 R1' - 1/R2^2 R2'
-1/625E4 R' = -1/25E6 * 330 - 1/25E6 * 660
1/625E4 R' = 990/25E6
R' = 990*625E4/25E6 = 990*625/2500
R' = 247.5 ω/s
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.