Asked by Joan
                Three resistors (14.4 Ω, 21.7 Ω, 14.1 Ω) are connected in parallel across 98 V. What is the total resistance for this circuit? What is the voltage drop across the 21.7 Ω resistor? What current is flowing in the 14.1 Ω resistor? What is the total circuit current? What power is dissipated at the 14.4 Ω resistor? 
            
            
        Answers
                    Answered by
            bobpursley
            
    I will be happy to critique your thinking.
    
                    Answered by
            Anonymous
            
    1/R=1/R1+1/R2=1/R3
    
                    Answered by
            Anonymous
            
    1/R=1/R1+1/R2+1/R3
    
                    Answered by
            Henry
            
    E = 98 V.
R1 = 14.4 Ohms
R2 = 21.7 Ohms
R3 = 14.1 Ohms.
a. 1/Rt = 1/R1+1/R2+1/R3
1/Rt = 1/14.4 + 1/21.7 + 1/14.1 =
0.186449 Mhos
Rt = 5.36 Ohms
b. V1 = V2 = V3 = E = 98 V.
c. I3 = E/R3 = 98/14.1 = 6.95A
d. I = E/Rt = 98/5.36 = 18.3A
e. P1 = E^2/R1 = 98^2/14.4 = 667 Watts
    
R1 = 14.4 Ohms
R2 = 21.7 Ohms
R3 = 14.1 Ohms.
a. 1/Rt = 1/R1+1/R2+1/R3
1/Rt = 1/14.4 + 1/21.7 + 1/14.1 =
0.186449 Mhos
Rt = 5.36 Ohms
b. V1 = V2 = V3 = E = 98 V.
c. I3 = E/R3 = 98/14.1 = 6.95A
d. I = E/Rt = 98/5.36 = 18.3A
e. P1 = E^2/R1 = 98^2/14.4 = 667 Watts
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