HAc + NH3 ==> NH4Ac
0.056..0.064.....
Since these are 1:1 (1 mole HAc neutralizes exactly 1 mole NH3), then you can see that you can't react more than 0.056. So all of the HAc reacts and leaves 0.064-0.056 = 0.008 mole NH3 unreacted. How much NH4Ac is formed. 0.056 mole of course.
if you add 0.056 moles of HC2H3O2 to 0.064 moles of NH3, how many moles of each are actually neutralized?
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