Asked by ashley

an antelope moving with constant acceleration covers the distance between two points that are 80 meters apart in 7 seconds. Its velocity as it passes the second point is 15 meters per second.




What is the antelope's velocity at the first point?

What is the acceleration ?





Answers

Answered by Damon
say x = 0 at start, t = 0
x = 80 at t = 7
v = 15 at x = 80 and t = 7

v = Vo + a t

x = 0 + Vo t + .5 a t^2

so
15 = Vo + 7 a
80 = Vo (7) +.5 a (49)
solve those two equations for Vo and a
Answered by ashley
could you explain simpler . i get condfused easily im in 10th grade taking 12 grade classes its tough. any help will do
Answered by Damon
ok, you have 2 equations in your physics book for constant acceleration

velocity = initial velocity + acceleration times time
or
v = Vo + a t

position = initial position + initial velocity times time + half of acceleration times time squared
or
x = Xo + Vo t +(1/2) a t^2

here I called Xo, initial position zero and x after 7 seconds was 80
so
80 = 0 + Vo (7) + (1/2) a (7)^2

and I know final velocity at t = 7 is 15 but I do not know Vo
so
15 = Vo + a (7)
Answered by Observer
Obviously, you're in over your head. Maybe you should be taking 10th grade classes.
Answered by Damon
They may have used different letters and so forth, but the equations are there in the book I am sure.
Answered by Damon
ashley got the function stuff ok and we will get this as well.
Answered by ashley
i know this . im doing well i just need a little help
Answered by ashley
thank you damon. i know we will
Answered by harambe
not me
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