(a) Vav *t = [(V2 + V1)/2]*7 = 70
V2 = 15
V2/2 = 7.5 = 10 - (V1/2)
V1/2 = 2.5
V1 = 5 m/s
a = (V2 - V1)/t = 10/7.00 m/s^2
An antelope moving with constant acceleration covers the distance between two points 70.0
m apart in 7.00 s. Its speed as it passes the second point is 15.0 m/s. (a) What is its speed at the first
point? (b) What is its acceleration?
2 answers
Solution