Asked by Anonymous
at what points on the hyperbola xy=12 is the tangent line parrallel to the line y= -3x
Answers
Answered by
bobpursley
slope= -3
y=12/x
y'=-3=-12/x^2
x^2=4
x=+-2
check that
y=12/x
y'=-3=-12/x^2
x^2=4
x=+-2
check that
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