Asked by xavier
Consider the hyperbola y = 1/x and think of it as a slide. A particle slides along the hyperbola so that its x-coordinate is increasing at a rate of f(x) units/sec. If its y-coordinate is decreasing at a constant rate of 1 unit/sec, what is f(x)?
-I arrived at the answer f(x)= x^2 but i am not quite sure about my answer, pls help for my assigment.
-I arrived at the answer f(x)= x^2 but i am not quite sure about my answer, pls help for my assigment.
Answers
Answered by
Steve
y = 1/x
dy/dt = -1/x^2 dx/dt
-1 = -1/x^2 dx/dt
dx/dt = x^2
Looks good to me.
dy/dt = -1/x^2 dx/dt
-1 = -1/x^2 dx/dt
dx/dt = x^2
Looks good to me.