Asked by Amanda
Okay so I kinda understand where to put the numbers into the formula but i'm not sure how to calculate the distance so could someone kindly walk me through the problem so i can understand it. Thank you so much.
Calculate the amount of energy required for the formation of one mole of BeS bonds (not lattice energy). The radius of the beryllium ion is 0.31 A (has a squiggle on the top), and the radius of the sulfide ion is 1.84 A (has a squiggle on top also). Note that 1A (has a squiggle) = 10^-10m.
I'm suppose to use the formula E=(kq1q2)/d
k is the constant 2.31 * 10^-28 J*m
Calculate the amount of energy required for the formation of one mole of BeS bonds (not lattice energy). The radius of the beryllium ion is 0.31 A (has a squiggle on the top), and the radius of the sulfide ion is 1.84 A (has a squiggle on top also). Note that 1A (has a squiggle) = 10^-10m.
I'm suppose to use the formula E=(kq1q2)/d
k is the constant 2.31 * 10^-28 J*m
Answers
Answered by
DrBob222
E in joules = kq1q2/d
k you have in the problem
q1 = 2
q2 = 2
d = radius anion + radius cation = 1.84+0.31 = ? and convert to meters.
Substitute and solve.
k you have in the problem
q1 = 2
q2 = 2
d = radius anion + radius cation = 1.84+0.31 = ? and convert to meters.
Substitute and solve.
Answered by
nicole
Calculate the amount of energy released in the formation of one mole of BaSe bonds (not lattice energy). The radius of the barium ion is 1.35 Å, and the radius of the selenide ion is 1.98 Å. Note that 1Å=10−10m. needs to be using the dimensions of enthalpy for the answer
Answered by
Anonymous
falds
Answered by
sarah
Calculate the amount of energy released in the formation of one mole of BaSe bonds (not lattice energy). The radius of the barium ion is 1.35 Å, and the radius of the selenide ion is 1.98 Å. Note that 1Å=10−10m. needs to be using the dimensions of enthalpy for the answer
Answered by
fda
fda
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