Asked by allysa
i kinda need help with these 2 please:
assume (y) varies direcly as (x)
if (x)=32 when (y)=6, what is the value of k?
and
(y) varies directly as (x)
find the constant when (x)=0.5, and
(y)=0.3
and can someone also explain what they mean by find the constant and how 2 do it in the 2nd one please? thank u
assume (y) varies direcly as (x)
if (x)=32 when (y)=6, what is the value of k?
and
(y) varies directly as (x)
find the constant when (x)=0.5, and
(y)=0.3
and can someone also explain what they mean by find the constant and how 2 do it in the 2nd one please? thank u
Answers
Answered by
bobpursley
y=kx
6=k*32 or
k=6/32 or 3/16 on the first.
One the second, y=kx, again, solve for the constant k.
6=k*32 or
k=6/32 or 3/16 on the first.
One the second, y=kx, again, solve for the constant k.
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