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i kinda need help with these 2 please:

assume (y) varies direcly as (x)
if (x)=32 when (y)=6, what is the value of k?

and

(y) varies directly as (x)
find the constant when (x)=0.5, and
(y)=0.3


and can someone also explain what they mean by find the constant and how 2 do it in the 2nd one please? thank u
16 years ago

Answers

bobpursley
y=kx
6=k*32 or
k=6/32 or 3/16 on the first.

One the second, y=kx, again, solve for the constant k.
16 years ago

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