q = mass H2O x deltaHvap. You list delta Hvap for H2O as 44 kJ but "per WHAT"
If that is per grams use grams for mass H2O. If that is per mole, use moles for mass H2O.
Given the following reaction and enthalpy change, calculate the amount of heat for converting 100.4g of liquid water (18.02g/mole) to a vapor?
delta H= +44kJ
1 answer