Asked by pakilina
A man whose mass is 70 kg walks up to the third floor of a building. This is a vertical height of 12 m above the street level.
(a) How many joules of work has he done?
(b) By how much has he increased his potential energy?
(c) If he climbs the stairs in 20 sec, what was his rate of work, ie. power?
(a) How many joules of work has he done?
(b) By how much has he increased his potential energy?
(c) If he climbs the stairs in 20 sec, what was his rate of work, ie. power?
Answers
Answered by
Henry
Fm = mg = 70ikg * 9.8N/kg = 686N. = Force of the man.
a. W = Fm*d = 686 * 12 = 8232J.
b. PE = mg*h = 686 * 12 = 8232J.
c. P = F * d/t = 686 * 12/20 = 411.6J/s = 411.6 Watts.
a. W = Fm*d = 686 * 12 = 8232J.
b. PE = mg*h = 686 * 12 = 8232J.
c. P = F * d/t = 686 * 12/20 = 411.6J/s = 411.6 Watts.
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