Asked by Patricia

A hiker, of mass 80 kg walks up a mountain, 700 m above sea level, to spend the night at the top in the first overnight hut. The second day she walks to the second overnight hut, 400 m above sea level. The third day she returns to her starting point, 200 m above sea level.
How much potential energy has the hiker lost in the second day?
Answered by R_scott
m * g * Δh = 80 kg * 9.8 m/s^2 * (700 m - 400 m) = ? Joules
Answered by ayooo wyddd!!!!!!
idk idk idk idk idk idk idk idk idk idk idk idk idk idk idk idk idk!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
There are no AI answers yet. The ability to request AI answers is coming soon!