Asked by anna
water at 20°C has viscosity n=1.0*10^-3 Ns/m^2. sand grains have density 2400kg/m^3. suppose a 1.1 mm diameter sand grain is dropped into a 51m deep lake whose water is a constant 20°C. If the sand grain reaches terminal speed almost instantly (a quite good approximation), how long will it take the sand grain to settle to the bottom of the lake?
Answers
Answered by
drwls
Use Stokes' drag equation for the terminal velocity.
Stoke's equation says, for a sphere in a viscous fluid,
F=6(pi)RnVc,
where F is the force, R is the radius of the sphere, n is the viscosity, and V is the velocity through the fluid.
For the force F, use the weight minus the buoyancy force.
Divide the lake depth by that velocity.
Stoke's equation says, for a sphere in a viscous fluid,
F=6(pi)RnVc,
where F is the force, R is the radius of the sphere, n is the viscosity, and V is the velocity through the fluid.
For the force F, use the weight minus the buoyancy force.
Divide the lake depth by that velocity.
Answered by
drwls
Make that last term V, not Vc
Answered by
Mustafa Qader
a) Vterm = (mg)/(6pi N R)
b)V term = ((4/3)pi R^3)pg))/(6pi N R)
b)V term = ((4/3)pi R^3)pg))/(6pi N R)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.