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The curve
y = x/(1 + x^2)
is called a serpentine. Find an equation of the tangent line to this curve at the point (2, 0.40).
(Round the slope and y-intercept to two decimal places.)
13 years ago

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The curve
y = x/(1 + x^2)
is called a serpentine. Find an equation of the tangent line to this curve at the point (2, 0.40).
(Round the slope and y-intercept to two decimal places.)

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