Question

(5y-3)/3 - (2y-1)/2=1

note: the divide signs are the fraction bars.

-5(-2(x-1) - (x+1))=9

.08n-.09(n-2)=5-.08

-2(3-(x-1)+3x) + 2(x-3-5(x-3)-x)=10

please show me how you got the answers thanks

Answer 1

#1.
(5y-3)/3 - (2y-1)/2=1
[(5y-3)/3 - (2y-1)/2 = 1]*6
2(5y-3) - 3(2y-1) = 6
10y - 6 - 6y + 3 = 6
4y - 3 = 6
4y = 9
y = 9/4

#2.
-5(-2(x-1) - (x+1)) = 9
-5(-2x + 2 - x - 1) = 9
-5(-3x + 1) = 9
15x - 5 = 9
15x = 14
x = 14/15

#3.
.08n-.09(n-2)=5-.08
0.08n - 0.09n + 0.18 = 4.92
-0.01n = 4.74
n = -474

#4.
-2(3-(x-1)+3x) + 2(x-3-5(x-3)-x)=10
-2(3-x+1+3x) + 2(x-3-5x+15-x)=10
-2(2x + 4) + 2(12 - 5x) = 10
-4x - 8 + 24 - 10x = 10
-14x + 16 = 10
-14x = -6
x = 6/14 = 3/7

hope this helps~ :)

Answer 2

Thanks! :)