Asked by Christine
A 1000-kg car is driving toward the north along a straight road at a speed of 20.0 m/s. The driver applies the brakes and the car comes to a rest in a distance of 140 m. What is the constant force applied to the car to bring it to rest?
Answers
Answered by
bobpursley
force= mass*acceleration
What is acceleration?
vf^2=Vi^2+2ad solve for a.
What is acceleration?
vf^2=Vi^2+2ad solve for a.
Answered by
Mohamad
first:-
X=X1+0.5(Vx+V1x)t
140=0+0.5(20)t
t=14s
second:-
a=v/t=20/14=1.43m/s2
F=m*a=1000*1.43=1430N to the south
X=X1+0.5(Vx+V1x)t
140=0+0.5(20)t
t=14s
second:-
a=v/t=20/14=1.43m/s2
F=m*a=1000*1.43=1430N to the south
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