Asked by Anonymous
A 2.6 kg block of ice at a temperature of 0.0C
and an initial speed of 5.3 m/s slides across a
level floor.
If 3.3 × 105 J are required to melt 1.0 kg
of ice, how much ice melts, assuming that the
initial kinetic energy of the ice block is entirely
converted to the ice’s internal energy?
and an initial speed of 5.3 m/s slides across a
level floor.
If 3.3 × 105 J are required to melt 1.0 kg
of ice, how much ice melts, assuming that the
initial kinetic energy of the ice block is entirely
converted to the ice’s internal energy?
Answers
Answered by
Kathya
KE=1/2mv^2
KE=1/2(2.5kg)(5.7m/s)
KE=40.6J=1.230x10^-4kg
KE=1/2(2.5kg)(5.7m/s)
KE=40.6J=1.230x10^-4kg
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