Asked by mike
A 2.5 kg block of ice at a temperature of 0.0 degrees Celcius and an initial speed of 5.7 m/s slides across a level floor. If 3.3 x 10^5 J are required to melt 1.0 kg of ice, how much ice melts, assuming that the initial kinetic energy of the ice block is entirely converted to the ice's internal energy?
(Our teacher doesn't teach us, plus I'm not really geared towards physics. Any help provided would be appreciated.)
(Our teacher doesn't teach us, plus I'm not really geared towards physics. Any help provided would be appreciated.)
Answers
Answered by
drwls
What does your teacher do?
Compute the initial kinetic energy (KE) of the ice using
KE = (1/2) M V^2
You should get 40.6 Joules
Divide that by 3.3*10^5 J/kg to get the number of kg's that melt.
Very little ice melts compared to the mass of the block. No energy goes into raising the temperature because it stays at 0C until it all melts.
Compute the initial kinetic energy (KE) of the ice using
KE = (1/2) M V^2
You should get 40.6 Joules
Divide that by 3.3*10^5 J/kg to get the number of kg's that melt.
Very little ice melts compared to the mass of the block. No energy goes into raising the temperature because it stays at 0C until it all melts.
Answered by
mike
I almost forgot to thank you :)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.