Asked by Xie
how to find derivative of (2+cotx)/(7-tanx)
Answers
Answered by
Jai
the derivative of cot x = -csc^2 x
the derivative of tan x = sec^2 x
.. and you do this:
[ low*d(high) - high*d(low) ] / (low)^2
where
high = numerator
low = denominator
d(high) and d(low) = respective derivatives
the derivative of tan x = sec^2 x
.. and you do this:
[ low*d(high) - high*d(low) ] / (low)^2
where
high = numerator
low = denominator
d(high) and d(low) = respective derivatives
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.