Question
A 2kg hallow sphere of a radius 6cm starts from rest and rolls without slipping down a 10 degree incline. if the length of the incline is 50cm then the velocity of the center of mass of the hallow sphere at the bottom of the incline is?
Answers
bobpursley
if it rolling, then the angular velocity is related to velocity as
w=v/r
the energy gravity gives up is
mg(.50*sin10)
The energy in the sphere is
1/2 I w^2 + 1/2 m v^2=
1/2 I v^2/r^2+1/2 m v^2
look up I (moment of inertia) for a hollow sphere, set KE = initial PE, and solve for v. Your teacher is too easy.
w=v/r
the energy gravity gives up is
mg(.50*sin10)
The energy in the sphere is
1/2 I w^2 + 1/2 m v^2=
1/2 I v^2/r^2+1/2 m v^2
look up I (moment of inertia) for a hollow sphere, set KE = initial PE, and solve for v. Your teacher is too easy.