Asked by Jj
A sphere has a radius of 16 cm and a plane passes thru it at 9 cm below the center, what is the area of the intersection between the plane and the sphere?
Answers
Answered by
Reiny
Visualize slicing a nice round object such as an apple in the way you described.
Try to sketch a 3-D diagram.
Your slice will have a circular surface.
Sketch a right-angled triangle with hypotenuse of 16 and height of 9
The third side will the the radius of you circular slice.
r^2 + 9^2 = 16^
r^2 = 175
area of that circular slice = πr2
= 175π cm^2
Try to sketch a 3-D diagram.
Your slice will have a circular surface.
Sketch a right-angled triangle with hypotenuse of 16 and height of 9
The third side will the the radius of you circular slice.
r^2 + 9^2 = 16^
r^2 = 175
area of that circular slice = πr2
= 175π cm^2
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