Asked by Lala

The coefficient of static friction between the m = 2.95-kg crate and the 35.0° incline is 0.345. What minimum force must be applied to the crate perpendicular to the incline to prevent the crate from sliding down the incline?
Answered by drwls
The static friction force must equal the weight component dwn the incline.

(F + M*g*cos35)*Us = M g sin35

Solve for F
Answered by Henry
Post it.
Answered by Jason
Nice thank you! This worked perfectly!
Answered by Bob
what is g
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