The static friction force must equal the weight component dwn the incline.
(F + M*g*cos35)*Us = M g sin35
Solve for F
The coefficient of static friction between the m = 2.95-kg crate and the 35.0° incline is 0.345. What minimum force must be applied to the crate perpendicular to the incline to prevent the crate from sliding down the incline?
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Nice thank you! This worked perfectly!
what is g
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